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Chemistry
The de-Broglie wavelength of a ball of mass 10 g moving with a velocity of 10 ms -1 is [h=6.626 × 10-34 J s]
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Q. The de-Broglie wavelength of a ball of mass $10\, g$ moving with a velocity of $10\, ms ^{-1}$ is $\left[h=6.626 \times 10^{-34} J s\right]$
J & K CET
J & K CET 2011
Structure of Atom
A
$ 6.626\times 10^{-33}\,m $
54%
B
$ 6.626\times 10^{-29}\,m $
18%
C
$ 6.626\times 10^{-31}\,m $
16%
D
$ 6.626\times 10^{-36}\,m $
11%
Solution:
$ m=10\,g=0.01\,kg,\,v=10\,ms^{-1} $
According to de-Broglie equation,
$ \lambda =\frac{h}{mv} $
$ =\frac{6.626\times 10^{-34}}{0.01\times 10} $
$ =6.626\times 10^{-33}\,m $