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Q. The de Broglie wavelength of $1\, mg$ grain of sand blown by a $20 ms^{-1}$ wind is:

Structure of Atom

Solution:

$\lambda=\frac{h}{mv}=\frac{6.626\times10^{-34}}{1\times10^{-6}\times20}$
$= 3.13\times10^{-29}m$