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Q. The de-broglie wavelength associated with particle of mass $10^{-6} kg$ moving with a velocity of $10 m / sec$ is:

Structure of Atom

Solution:

According to de-Broglie equation

$\lambda=\frac{ h }{ mv }=\frac{6.63 \times 10^{-34}}{10^{-6} \times 10}$

$\Rightarrow \frac{6.63 \times 10^{-34}}{10^{-5}}$

$=6.63 \times 10^{-29} m$