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Q. The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of $100\,V$. What should nearly be the ratio of their wavelengths ? $\left( m _{ P }=1.00727\,u ,\,m _{ e }=0.00055\,u \right)$

JEE MainJEE Main 2021Dual Nature of Radiation and Matter

Solution:

$\lambda=\frac{ h }{ mv }=\frac{ h }{\sqrt{2 mK }}=\frac{ h }{\sqrt{2 mqV }}$
$\frac{\lambda_{1}}{\lambda_{2}}=\sqrt{\frac{ m _{2}}{ m _{1}}}$
$\frac{\lambda_{ e }}{\lambda_{ p }}=\sqrt{\frac{ m _{ P }}{ m _{ e }}}=\sqrt{1831.4}=42.79$