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Physics
The de -Broglie wavelength associated with an electron, accelerated through a potential difference of 100 volts is
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Q. The $de$ -Broglie wavelength associated with an electron, accelerated through a potential difference of $100$ volts is
NTA Abhyas
NTA Abhyas 2020
A
$0.529nm$
B
$52.9nm$
C
$0.123nm$
D
$1.23nm$
Solution:
Accelerating potential $V=100V$
$\lambda =\frac{h}{p}=\frac{1 . 227}{\sqrt{V}}nm$
$\lambda =\frac{1 . 227}{\sqrt{100}}nm=0.123nm$