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Q. The $de$ -Broglie wavelength associated with an electron, accelerated through a potential difference of $100$ volts is

NTA AbhyasNTA Abhyas 2020

Solution:

Accelerating potential $V=100V$
$\lambda =\frac{h}{p}=\frac{1 . 227}{\sqrt{V}}nm$
$\lambda =\frac{1 . 227}{\sqrt{100}}nm=0.123nm$