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Chemistry
The de-Broglie’s wavelength of electron present in first Bohr orbit of ‘H’ atom is :
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Q. The de-Broglie’s wavelength of electron present in first Bohr orbit of ‘H’ atom is :
JEE Main
JEE Main 2018
Structure of Atom
A
$0.529 \, \mathring{A}$
37%
B
$2 \pi \times 0.529 \, \mathring{A}$
49%
C
$\frac{0.529}{2\pi} \, \mathring{A}$
9%
D
$4 \times 0.529 \, \mathring{A}$
4%
Solution:
Bohr's radius of first stationary state is $r=0.529 \, \mathring{A}$
Angular momentum is given by $mvr=\frac{n h}{2 \pi}$
For first Bohr's orbit $n=1$
$2 \pi r =\frac{h}{m v}=\lambda $
$\lambda =2 \pi \times 0.529 \, \mathring{A}$