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  4. The 'd' orbital involved in the hybridisation in the PCl5 molecule is

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Q. The $ 'd' $ orbital involved in the hybridisation in the $ PCl_{5} $ molecule is

J & K CETJ & K CET 2009Chemical Bonding and Molecular Structure

Solution:

In $ PCl_{5}, $
No. of hybrid orbitals = no. of a bonds + lone pair
$ =5+0=5 $
Thus, hybridisation is $ sp^{3}d$.
The $d$-orbital involved in the
$ sp^{3}d $ hybridisation is $ 3d_{z^{2}}. $