1. Tardigrade
  2. Question
  3. Physics
  4. The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 Ω is mA.

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The cut-off voltage of the diodes (shown in figure) in forward bias is $0.6\, V$. The current through the resister of $40\, \Omega$ is _______$mA$.Physics Question Image

JEE MainJEE Main 2022Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

image
$1- I (60)-0.6- I (40)=0$
$\frac{0.4}{100}= I$
$I =4\, mA$