1. Tardigrade
  2. Question
  3. Physics
  4. The current voltage relation of diode is given by I = (e1000V/T — 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ±0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA ?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The current voltage relation of diode is given by $I = (e^{1000V/T} — 1)\, mA$, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring $±0.01\, V$ while measuring the current of $5 \,mA$ at $300\, K$, what will be the error in the value of current in $mA$ ?

JEE MainJEE Main 2014Physical World, Units and Measurements

Solution:

$I=\left(e^{1000 V / T }-1\right) mA $
When $ I=5 \,mA , e^{1000 V / T }=6\, mA$
Also, $d I=\left(e^{1000 V / T }\right) \times \frac{1000}{ T } \cdot d V $
$=(6 mA ) \times \frac{1000}{300} \times(0.01)$
$=0.2 \,mA$