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Q. The current passing through an inductor coil of 5H is decreasing at the rate of 2A/s, the emf developed across the coil is

ManipalManipal 2013Electromagnetic Induction

Solution:

If on changing current through the coil, the emf induced in the coil ise, then by Faradays 2nd law, we have
$ e=-L\frac{\Delta i}{\Delta t} $
where, $ \frac{\Delta i}{\Delta t} $ is rate of change of current.
Given, $ L=5H,\text{ }\frac{\Delta i}{\Delta t}=-2A/s $ (decreasing)
$ \therefore $ $ e=-5\times (-2)=+10V $