Q.
        The current in the $1\Omega$ resistor shown in the circuit is
      
          VITEEEVITEEE 2019
          
        
      Solution:
Two $4\Omega$ resistors are in parallel combination. Their equivalent resistance 
$=\frac{4\times4}{4+4}=\frac{16}{8}=2\Omega$ 
$\therefore $ Total resistance of the 
network $= 2 + 1 = 3\Omega$ 
$\therefore $ Current through $1\Omega$ resistor, $i=\frac{6}{3}=2A$