Q.
The current in the $1\Omega$ resistor shown in the circuit is
VITEEEVITEEE 2019
Solution:
Two $4\Omega$ resistors are in parallel combination. Their equivalent resistance
$=\frac{4\times4}{4+4}=\frac{16}{8}=2\Omega$
$\therefore $ Total resistance of the
network $= 2 + 1 = 3\Omega$
$\therefore $ Current through $1\Omega$ resistor, $i=\frac{6}{3}=2A$
