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  4. The current in a self inductance L = 40 mH is to be increased uniformly from 1A to 11A in 4 ms. The e.m.f induced in inductor during this process is

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Q. The current in a self inductance L = 40 mH is to be increased uniformly from 1A to 11A in 4 ms. The e.m.f induced in inductor during this process is

COMEDKCOMEDK 2004Electromagnetic Induction

Solution:

$\varepsilon = L \frac{di}{dt} = \frac{(40 \times 10^{-3} )(11 - 1)}{4 \times 10^{-3}}$ = 100 V