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Physics
The current I in the given circuit will be
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Q. The current $I$ in the given circuit will be
JEE Main
JEE Main 2022
Current Electricity
A
10A
58%
B
20 A
10%
C
4A
16%
D
40A
16%
Solution:
Given circuit is balanced wheat stone bridge Hence $2 \Omega$ can be neglected
$ R _{ net }=4 \Omega$
$ I =\frac{40}{4}$
$ I=10 A$