Question

The current $I$ in the circuit shown is

• A. 1.33 A
• B. Zero
• C. 2.00 A
• D. 1.00 A

Answer 1

Answer: (A)

The circuit diagram can be redrawn as

For the loop $A B C D A$,
$+2-2 I'+2-2 I=0$ ...(i)
For the loop $A B F E A$,
$2-2 I+2-2\left(I-I'\right)=0$
$4-2 I-2 I+2 I'=0$
$4-4 I+2 I'=0$
$2 =2 I-I'$ ...(ii)
From Eqs. (i) and (ii), we get
$2=2 I- I', 2=I+I'$
$4=3I,\, I=4 / 3=1.33\, A$