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  4. The current gain of a common base transistor circuit is 0.96. On changing the emitter current by 10.0 mA, the change in the base current will be

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Q. The current gain of a common base transistor circuit is 0.96. On changing the emitter current by 10.0 mA, the change in the base current will be

J & K CETJ & K CET 2011Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Current gain for common base transistor
$ \, \, \, \, \, \, \alpha=\bigg(\frac{\Delta I_C}{\Delta I_E}\bigg)_{V_C}$
Given, $ \, \, \, \, \, \, \, \, \alpha=0.96 , \Delta I_E =10.0mA$
$ \, \, \, \, \, \, \, \, \, \, 0.96=\frac{\Delta I_C}{10.0}$
$ \, \, \, \, \, \, \, \, \, \, \Delta I_C =0.96 \times 10.0 =9.6 mA$