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Chemistry
The Cu2+ in CaSO4-5H2O has a spin only magnetic moment of 1 -73 p.B. This indicates the pressure of
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Q. The $Cu^{2+}$ in $CaSO_4-5H_2O$ has a spin only magnetic moment of 1 -73 p.B. This indicates the pressure of
The d-and f-Block Elements
A
One unpaired electron
43%
B
Two unpaired electron
39%
C
Three unpaired electron
9%
D
Four unpaired electron
9%
Solution:
$\mu = \sqrt{n(n + 2)} \, \mu_b$ where $n$ = no. of unpaired electrons $\therefore $ 1.73 = $\sqrt{n(n+2)} \, \mu_b \, \therefore \, n = 1$