As $Na_2SO_4 . x H_2O$ on heating loses water, i.e., 55.9% = 56% of its weight. $ \therefore $ % of weight of $Na_2SO_4$ = 44% Molecular weight of $Na_2SO_4$ = 142 g $\therefore $ $\frac{w_{H_2O}}{w_{Na_2SO_4}} = \frac{56}{44}$ or $w_{H_2O} =\frac{56}{44} \times 142 = 180 \, g$ Thus, the formula of crystalline salt is $Na_2SO_4 . 10H_2O$.