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Chemistry
The Crystal Field Stabilisation Energy (CFSE) for [CoCl6]4- is 18000 cm-1. The CFSE for [CoCl4]2- will be-
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Q. The Crystal Field Stabilisation Energy (CFSE) for $[CoCl_6]^{4-}$ is $18000\, cm^{-1}$. The CFSE for $[CoCl_4]^{2-}$ will be-
NEET
NEET 2019
Coordination Compounds
A
$6000\, cm^{-1}$
6%
B
$16000\, cm^{-1}$
13%
C
$18000\, cm^{-1}$
14%
D
$8000 \,cm^{-1}$
67%
Solution:
$\Delta_{\text{tetrahedral}} = \frac{4}{9} \times \Delta_{\text{octahedral}}$
$ = \frac{4}{9} \times 18000$
$ = 8000 \,cm^{-1}$