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Q. The critical angle for total internal reflection in diamond is $ 24.5^{\circ} $ . The refractive index of the diamond is

Delhi UMET/DPMTDelhi UMET/DPMT 2009Ray Optics and Optical Instruments

Solution:

Given, critical angle $C=24.5^{\circ}$
For total internal reflection
$\mu=\frac{1}{\sin C} =\frac{1}{\sin 24.5^{\circ}} \mu$
$=2.45 \left[\sin 24.5^{\circ}=0.414\right]$