Question

The correct value of emf of cell is given by
(i) $E_{cell}=E_{OP} anode -E_{RP} cathode$
(ii)$E_{cell}=E_{OP} anode +E_{RP} cathode$
(iii) $E_{cell}=E_{RP} anode +E_{RP} cathode$
(iv) $E_{cell}=E_{OP} anode -E_{OP} cathode$

• A. (iii) and (i)
• B. (i) and (ii)
• C. (iii) and (iv)
• D. (ii) and (iv)

Answer 1

Answer: (D)

$E_{cell}= E_{OPanode} + E_{RPCathode} = E_{OPanode} -E_{OPcathode}$