Question

The correct symbol of the species with number of electrons, protons and neutrons as $ 18,16 $ and $ 16 $ respectively is

• A. $ ^{32}_{16}S $
• B. $ ^{32}_{18}S $
• C. $ ^{32}_{16}S^{2-} $
• D. $ ^{32}_{18}S^{2-} $

Answer 1

Answer: (C)

Number of protons = Atomic number = $16$
Thus, the element is sulphur
Further, mass number = number of protons + number of neutrons $=16 + 16 = 32$
Since, number of electrons are greater than the number of protons, so it must be an anion (i.e., obtained by accepting two electrons Hence, the correct symbol of the species must be $^{32}_{16}S^{2-}$