Question

The correct representation of Nernst’s equation is

• A. $E_{M^{n+}/M}=E^{o}_{M^{n+}M}+\frac{n}{0.0591}log\left(M^{n+}\right)$
• B. $E_{M^{n+}/M}=E^{o}_{M^{n+}M}-\frac{n}{0.0591}log\left(M^{n+}\right)$
• C. $E_{M^{n+}/M}=E^{o}_{M^{n+}M}+\frac{0.591}{n}log\left(M^{n+}\right)$
• D. None of the above

Answer 1

Answer: (C)

$E=E^{o}-\frac{RT}{nF}In \frac{1}{\left[M^{n+}\right]};E=E^{o}+\frac{RT}{nF}ln \left[M^{n+}\right] $
$E=E^{o}+\frac{2.303 RT}{nF}log \left[M^{n+}\right]$
Substituting the value of $R, T (298K)$ and $F$ we get
$E=E^{o}+\frac{0.0591}{n}log\left(M^{n+}\right)$