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  4. The correct relationship between free energy and equilibrium constant K of a reaction is

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Q. The correct relationship between free energy and equilibrium constant K of a reaction is

Thermodynamics

Solution:

The relation between free energy change and equilibrium constant is given by Nernst equation
$E = E^{\circ} - \frac{RT}{nF} ln \, Q$
At equilibrium, $E_C = 0$ and $Q = K_C$
$\therefore \, E^{\circ} = \frac{RT}{nF} ln \, K$ ......(i)
Again $\Delta G^{\circ} = nFE^{\circ}$ .....(ii)
Put in (i)
$\frac{- \Delta G^{\circ}}{nF} = \frac{RT}{nF} ln K ; \Delta G^{\circ} = - RT lnK$