Question

The correct relation between equilibrium constant (K), standard free energy $ (\Delta G{}^\circ ) $ and temperature (T) is

• A. $ \Delta G{}^\circ =RT\,\ln K $
• B. $ K={{e}^{-\Delta G{}^\circ /2303RT}} $
• C. $ \Delta G{}^\circ =-RT{{\log }_{10}}K $
• D. $ K={{10}^{-\Delta G{}^\circ /2.303\,RT}} $

Answer 1

Answer: (D)

The relationship between equilibrium constant (K), standard free energy $ (\Delta G{}^\circ ) $ and temperature $ (T) $ is given as $ \Delta G{}^\circ =-\,2.303\text{ }RT\,\,\log \,K $ $ -\frac{\Delta G{}^\circ }{2.303RT}=\log K $ $ K={{10}^{-\Delta G{}^\circ /2.303\,RT}} $