Question

The correct order regarding the electronegativity of hybrid orbitals of carbon is

• A. $s p < s p^{2} < s p^{3}$
• B. $s p >s p^{2} < s p^{3}$
• C. $s p>s p^{2}>s p^{3}$
• D. $s p < s p^{2} > s p^{3}$

Answer 1

Answer: (C)

More then s-character more closer towards the nucleus more will be the electronegativity