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Chemistry
The correct order of number of unpaired electrons is
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Q. The correct order of number of unpaired electrons is
The d-and f-Block Elements
A
$Cu^{2+} > Ni^{2+} > Cr^{3+} > Fe^{3+}$
11%
B
$Ni^{2+} > Cu^{2+} > Fe^{3+} > Cr^{3+}$
6%
C
$Fe^{3+} > Cr^{3+} >Ni^{2+} > Cu^{2+}$
74%
D
$Cr^{3+} > Fe^{3+} >Ni^{2+} > Cu^{2+}$
9%
Solution:
$Fe^{3+} - 3d^5$ No. of unpaired electrons $= 5$
$Cr^{3+} - 3d^3$ No. of unpaired electrons $= 3$
$Ni^{2+} - 3d^8$ No. of unpaired electrons $= 2$
$Cu^{2+} - 3d^9$ No. of unpaired electrons $= 1$