Question

The correct order of ionic size in polar solvent is

• A. $Li^{+}>Na^{+}>K^{+}>Rb^{+}$
• B. $Rb^{+}>K^{+}>Na^{+}>Li^{+}$
• C. $K^{+}>Na^{+}>Li^{+}>Rb^{+}$
• D. $Rb^{+}>Na^{+}>K^{+}>Li^{+}$

Answer 1

Answer: (A)

In polar solvent, solvation is maximum for $Li^{+}$ , due to high charge density on small size. Hence size of solvated cation is in the order $Li^{+}>Na^{+}>K^{+}>Rb^{+}$