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  4. The correct order of decreasing H-C-H angle in the following molecules is

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Q. The correct order of decreasing $H-C-H$ angle in the following molecules isChemistry Question Image

WBJEEWBJEE 2014

Solution:

$H - C - H$ bond angle is about $120^{\circ}$, when $C$ is bonded through a double bond but in case of $CH _{4}$, the $H-C-H$ bond angle is only $109^{\circ} 28^{\prime}$. Cyclic compounds have a $H-C-H$ bond angle greater than $109^{\circ} 28^{\prime}$ due to hindrance. Thus, the correct order of $H - C - H$ bond angle is $II > I > III$
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