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  4. The correct order of bond dissociation energy among N2, O2, O2- is shown in which of the following arrangements ?

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Q. The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements ?

JEE MainJEE Main 2014Chemical Bonding and Molecular Structure

Solution:

Bond energy $\propto$ Bond order bondorder :-

$N_{2} =Nb=10, Na=4$

$B.O.=\left(N_{2}\right)=\frac{10-4}{2}=3$

$O_{2}=Nb=10, Na=6$

$B.O_{\left(o_2\right)}=\frac{10-6}{2}=2$

$O_{2}^{-}=Nb=10, Na=7$

$B.O._{\left(o_2\right)}=\frac{10-7}{2}=\frac{3}{2}=1.5$

Hence the order of B.O.

$N_{2}>\, O_{2} >\, O_{2}^{-}$