Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The correct graph representing the variation of total energy $(E_t)$, kinetic energy $(E_k)$ and potential energy $(U)$ of a satellite with its distance from the centre of earth is

Gravitation

Solution:

$U =\frac{-GMm}{r}, K = \frac{GMm}{2r} $ and $E = \frac{-GMm}{2r}$
For a satellite $U, K$ and $E$ vary with $r$ and also $U$ and $E$ remain negative whereas $K$ remains always positive.