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Q. The correct geometry and hybridization for $XeF_4$ are

NEETNEET 2016Chemical Bonding and Molecular Structure

Solution:

$XeF _{4}$ is $AB _{4} L _{2}$ in which the Xenon is bonded with four fluorine atoms with 4 sigma bonds and xenon has two lone pairs (4 sigma bonds and 2 lone pairs).
So, the hybridisation is $sp ^{3} d ^{2}$.
Geometry is octahedral and shape is square planar.