1. Tardigrade
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  3. Chemistry
  4. The correct equation of equilibrium constant in terms of Gibbs energy is

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Q. The correct equation of equilibrium constant in terms of Gibbs energy is

Equilibrium

Solution:

$\Delta G=\Delta G^{\circ}+R T \ln Q$
At equilibrium, when $\Delta G=0$ and
$Q=K_{C}$, the equation becomes,
$ \Delta G =\Delta G^{\circ}+R T \ln K=0 $
$ \Delta G^{\circ} =-R T \ln K $
$ \ln K =-\Delta G^{\circ} / R T $
Taking antilog on both sides, we get,
$K=e^{-\Delta G^{\circ} / R T}$