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Q. The correct equation for the degree of association $'\alpha'$ of an associating solute, $'n'$ molecules of which undergoes association in solution, is

KEAMKEAM 2015Solutions

Solution:

$n A \quad \Leftrightarrow A_{n}$

1 mole

$1-\alpha \quad \frac{\alpha}{n}, \quad$ Total $=1-\alpha+\frac{\alpha}{n}$

$\therefore i=1-\alpha+\frac{\alpha}{n}$ or $1-i=\alpha-\frac{\alpha}{n}=\alpha\left(1-\frac{1}{n}\right)$

$=\alpha\left(\frac{n-1}{n}\right)$

or $\alpha=\frac{n}{(n-1)}(i-i)=\frac{n(i-1)}{(1-n)}$