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Q.
The correct dimensions of the coefficient of viscosity are
NTA AbhyasNTA Abhyas 2020Physical World, Units and Measurements
Solution:
Viscous force is given as, $F =6 \pi \eta rv$.
$\therefore \eta=\frac{ F }{6 \pi rv }$
$[\eta]=\frac{[ F ]}{[ r ][ v ]}$
$[\eta]=\frac{\left[ MLT ^{-2}\right]}{[ L ]\left[ LT ^{-1}\right]}$