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Q. The copper (II) halide which does not exist is

AP EAMCETAP EAMCET 2019

Solution:

$CuI _{2}$ is not stable and thus does not exist iodide ion will act as reducing agent that converts $Cu(II)$ to $Cu(I)$ and part of iodide ion will be oxidised to iodine. The first reaction involved is as follows:

$2 Cu ^{2+}(a q)+4 I ^{-}(a q) \longrightarrow 2 \operatorname{CuI}(s)+ I _{2}(a q)$