Question

The coordination number of $N i^{2+}$ is $4$ .
$NiCl _{2}+ KCN$ (excess) $\rightarrow A$ (cyano complex)
$NiCl _{2}+$ conc. $HCl$ (excess) $\rightarrow B$ (chloro complex)
The IUPAC names of $A$ and $B$ are

• A. Potassium tetra cyano nickelate (II), potassium tetra chloro nickelate (II).
• B. Tetra cyano potassium nickelate (II), tetera chloro potassium nickelate (II).
• C. Tetra cyano nickel (II), tetra chloro nickel (II).
• D. Potassium tetra cyano nickel (II), potassium tetra chloro nickel (II).

Answer 1

Answer: (A)

$NiCl _{2}+4 KCN \rightarrow K _{2}\left[ Ni ( CN )_{4}\right]+2 KCl $,
$ IUPAC$ name is Potassium tetracyanonickelate (II)
$NiCl _{2}+2 KCl +$ conc $HCl \rightarrow K _{2}\left[ Ni ( Cl )_{4}\right]$,
$IUPAC$ name is Potassium tetrachloronickelate (II)