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Q.
The coordinates of P and Q are (-3, 4) and (2, 1), respectively. If PQ is extended to R such that PR = 2QR, then what are the coordinates of R ?
Straight Lines
Solution:
As given :
Coordinates of P and Q are (- 3, 4) and (2, 1) respectively.
Let coordinates of R be (x, y).
As given : PR = 2 QR
$\Rightarrow $ PR - QR = QR
$\Rightarrow $ PQ = QR.
So, Q is the mid point of P and R
$ \Rightarrow 2 = \frac{ -3+x}{22}$ and $ = \frac{4+y}{2} $
$\Rightarrow x = 7$ and $ y=-2$
$ \therefore $ Coordinates of $R \equiv\left(7,-2\right) $