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Q. The coordinates of centre of mass of the following quarter circular arc is -



Question

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
$dm=\lambda Rd\theta \, =\frac{2 m}{\pi }d\theta $
$\therefore x_{c m} \, =\frac{1}{m}\displaystyle \int x d m$
$=\frac{1}{m}\displaystyle \int _{0}^{\pi / 2} R cos \theta \frac{2 m}{\pi } d \theta $
Similarly $y_{c m}=\frac{1}{m}\displaystyle \int _{0}^{\frac{\pi }{2}} R \, sin . \theta \frac{2 m}{\pi } d \theta $