1. Tardigrade
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  4. The conveyor belt is moving at 4 m / s. The coefficient of static friction between the conveyor belt and the 10 kg package B is μs=0.2. Determine the shortest time (in s) in which the belt can be stopped so that the package does not slide on the belt.

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Q. The conveyor belt is moving at $4\,m / s$. The coefficient of static friction between the conveyor belt and the $10 \,kg$ package $B$ is $\mu_{s}=0.2$. Determine the shortest time (in $s$) in which the belt can be stopped so that the package does not slide on the belt.Physics Question Image

Laws of Motion

Solution:

$a_{\max }=\mu_{s} g=0.2 \times 10=2 \,m / s ^{2}$
$t_{\min }=\frac{u}{a_{\max }}=\frac{4}{2}=2 \,s$