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Chemistry
The conversion of A arrow B follows second order kinetics. If [A] is increased 3 times then rate of formation of [B] is
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Q. The conversion of $A \rightarrow B$ follows second order kinetics. If $[A]$ is increased 3 times then rate of formation of $[B]$ is
JIPMER
JIPMER 2015
Chemical Kinetics
A
increased 3 times
16%
B
decreased 3 times
12%
C
increased 9 times
67%
D
decreased 6 times
5%
Solution:
For a second order kinetics, rate = $k[A]^2$. If concentration of $A$ is increased by three times, rate = $k[3A]^2$. Hence, the rate of formation of $[B]$ increases 9 times.