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Q. The conjugate of the complex number $\frac{2+5 i }{4-3 i }$ is equal to:

Complex Numbers and Quadratic Equations

Solution:

Let $z=\frac{2+5 i}{4-3 i}$ Rationalize $=\frac{2+5 i}{4-3 i} \times \frac{4+3 i}{4+3 i}$
$=\frac{8+26 i-15}{(4)^{2}-(3 i)^{2}}=\frac{8+26 i-15}{16+(9)}=\frac{-7+26 i}{25}$