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Chemistry
The conjugate base of H2PO4 - is
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Q. The conjugate base of $H_2PO_4^ -$ is
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Equilibrium
A
$PO_4^{ 3-}$
B
$HPO_4^{ 2-}$
C
$H_3PO_4$
D
$P_2O_5$
Solution:
$\because 6.02×10^{+20}$ molecules of urea is present in $= \frac{0.0001\times1000}{100} = 0.01 M$