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Chemistry
The conjugate base of H2PO4- is
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Q. The conjugate base of $ {{H}_{2}}P{{O}_{4}^-} $ is
Manipal
Manipal 2010
Equilibrium
A
$ PO_{4}^{3-} $
33%
B
$ {{P}_{2}}{{O}_{5}} $
0%
C
$ {{H}_{3}}P{{O}_{4}} $
0%
D
$ HPO_{4}^{2-} $
67%
Solution:
Acid $- H^+ \to$ conjugate base
$ \therefore H_2PO_4^- - H^+ \to HPO_4^{2-} $
$ \therefore $ $ HPO_{4}^{2-} $ is the conjugate base of $ H_2PO_4^-$ .