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Chemistry
The conjugate acid and base of HPO2-4 respectively are
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Q. The conjugate acid and base of $HPO^{2-}_{4}$ respectively are
COMEDK
COMEDK 2010
Equilibrium
A
$PO^{3-}_{4}$ and $H_2 PO^{-}_{4}}
15%
B
$H_2 PO^{-}_{4}$ and $PO^{3-}_{4}$
61%
C
$H_3 PO_{4}$ and $PO^{3-}_{4}$
20%
D
$H _2 PO _4^{-}$and $H _2 PO _4$
5%
Solution:
$\underset{\text{Acid}}{HPO _4^{2-}}+ H ^{+} \longrightarrow \underset{\text{Conjugate base}}{PO _4^{3-}}$ $\underset{\text{Acid}}{HPO _4^{2-}}+ H ^{+} \longrightarrow \underset{\text{Conjugate base}}{H_2PO _4^{3-}}$