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Q. The conjugate acid and base of $HPO^{2-}_{4}$ respectively are

COMEDKCOMEDK 2010Equilibrium

Solution:

$\underset{\text{Acid}}{HPO _4^{2-}}+ H ^{+} \longrightarrow \underset{\text{Conjugate base}}{PO _4^{3-}}$ $\underset{\text{Acid}}{HPO _4^{2-}}+ H ^{+} \longrightarrow \underset{\text{Conjugate base}}{H_2PO _4^{3-}}$