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Q. The concentration of an organic compound in chloroform is $6.15\, g$ per $100 \,mL$ of solution. A portion of this solution in a $5 cm$ polarimeter tube causes an observed rotation of $-1.2^{\circ} .$ What is the specific rotation of the compound?

VITEEEVITEEE 2009

Solution:

$[\alpha]=\frac{[\alpha]_{\text {observed }}}{l \times C}=\frac{-1.2}{5 \times \frac{6.15}{1000}}=-39^{\circ}$