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Q.
The compound that will react most readily with NaOH to form methanol is
Alcohols Phenols and Ethers
Solution:
Compound $(CH_{3})_{4}N^{+}I^{-}$ is most reactive due to (i) better leaving group, $I^{-}$ and (ii) due to the fact that the methyl group, with positive N, is not more electron deficient
Hence this group is more reactive towards nucleophile, $OH^{-}$