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Q. The compound that gives a basic solution in $HF$ is

The p-Block Elements - Part2

Solution:

As $F _{5}+2 HF \rightleftharpoons\left[ AsF _{6}\right]^{-}+\left[ H _{2} F \right]^{+}$

$PF _{5}+2 HF \rightleftharpoons\left[ PF _{6}\right]^{-}+\left[ H _{2} F \right]^{+}$

$BF _{3}+2 HF \rightleftharpoons\left[ BF _{4}\right]^{-}+\left[ H _{2} F \right]^{+}$

$BrF _{3}+ HF \rightleftharpoons\left[ BrF _{2}\right]^{+}+\left[ H _{2} F _{2}\right]$

$BrF _{3}$ act as a base as it donate $F^-$ in $HF$