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Q. The compound formed by the reaction of ethyl-bromide and alcoholic $ KOH $ is:

Rajasthan PMTRajasthan PMT 1999

Solution:

$ {{C}_{2}}{{H}_{5}}Br\xrightarrow{alc.\,KOH}\underset{Acetylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\, $