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Chemistry
The complex ion [Cu(NH3)4]2+ has
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Q. The complex ion $[Cu(NH_3)_4]^{2+}$ has
Coordination Compounds
A
the tetrahedral configuration with one unpaired electron configuration
40%
B
square planar configuration with one unpairedelectrons
40%
C
tetrahedral configuration with all electrons paired
7%
D
square planar configuration will all electrons paired
13%
Solution:
$dsp^2$-hybridisation, square planar, one unpaired electron