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Chemistry
The complex CoCl3.3NH3 ionizes to give
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Q. The complex $CoCl_3.3NH_3$ ionizes to give
Coordination Compounds
A
$2Cl^-$ ion
13%
B
$1Cl^-$ ion
11%
C
$3Cl^-$ ion
33%
D
$0Cl^-$ ion
43%
Solution:
The complex $CoCl_3.3NH_3$ which has no ionisable chlorine is $[Co(NH_3)_3Cl_3]$.